∫Calc Practice

Divergence and curl at a point

Problem 12.348 · easy

Find the divergence and the curl of \( \displaystyle \mathbf F = \left\langle x + y, y + z, x + z \right\rangle \) at \( \displaystyle (2, -1, 3) \).
  1. \[ \left. \frac{\partial}{\partial x} \left(x + y\right) + \frac{\partial}{\partial z} \left(x + z\right) + \frac{\partial}{\partial y} \left(y + z\right) \right|_{\substack{ x=2\\ y=-1\\ z=3 }} = 3 \]
    div F = P_x + Q_y + R_z, at the point.✓ Proved
  2. \[ \left[\begin{matrix}\left. \frac{\partial}{\partial y} \left(x + z\right) - \frac{\partial}{\partial z} \left(y + z\right) \right|_{\substack{ x=2\\ y=-1\\ z=3 }}\\\left. \frac{\partial}{\partial z} \left(x + y\right) - \frac{\partial}{\partial x} \left(x + z\right) \right|_{\substack{ x=2\\ y=-1\\ z=3 }}\\\left. - \frac{\partial}{\partial y} \left(x + y\right) + \frac{\partial}{\partial x} \left(y + z\right) \right|_{\substack{ x=2\\ y=-1\\ z=3 }}\end{matrix}\right] = \left[\begin{matrix}-1\\-1\\-1\end{matrix}\right] \]
    curl F = ⟨R_y − Q_z, P_z − R_x, Q_x − P_y⟩, at the point.✓ Proved
Answer \( \nabla\cdot\mathbf F = 3,\quad \nabla\times\mathbf F = \left\langle -1, -1, -1 \right\rangle \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0central differences of F at the point

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the definitions of divergence and curl. The algebraic derivations are verified as correct, and the evaluation at the specified point is accurate.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly applies the definitions of divergence and curl. The algebraic derivations are verified as correct, and the evaluation at the specified point is accurate.
  • gpt-oss:20b: pass 2026-10-17
  • qwen3.6:27b-mlx: pass 2026-10-15
  • gpt-oss:20b: pass 2026-10-15
  • qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly applies the definitions of divergence and curl. The algebraic substitutions and evaluations at the specified point are accurate.
  • gpt-oss:20b: pass 2026-10-14

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/div_curl_point, checked 2026-10-17 with SymPy 1.14.0.