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Area with Green's theorem

Problem 12.272 · easy

Use Green's theorem to evaluate \( \displaystyle \oint_C \left(- x y^{2}\right) dx + \left(2 x\right) dy \), where \( \displaystyle C \) is the circle \( \displaystyle x^2 + y^2 = 1 \), oriented counterclockwise.

\[ \frac{d}{d x} 2 x - \frac{\partial}{\partial y} \left(- x y^{2}\right) = 2 x y + 2 \]
∂Q/∂x − ∂P/∂y.✓ Proved
\[ \int\limits_{0}^{2 \pi}\int\limits_{0}^{1} r \left(2 r^{2} \sin{\left(\theta \right)} \cos{\left(\theta \right)} + 2\right)\, dr\, d\theta = 2 \pi \]
∬_D (∂Q/∂x − ∂P/∂y) dA in polar coordinates.✓ Proved

Answer \( 2 \pi \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt

Line	Status	Checked by	Detail
1	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
2	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
answer, a second way	✓ Checked independently	sympy 1.14.0 + mpmath 1.3.0	the line integral around the boundary, computed directly

Reviewers

gpt-oss:20b: pass
qwen3.6:27b-mlx: pass — The solution correctly applies Green's Theorem, computes the partial derivatives accurately, and sets up the polar integral with the correct Jacobian and bounds for the unit disk.

Every verdict on record (4)

gpt-oss:20b: pass 2026-10-09
qwen3.6:27b-mlx: pass 2026-10-09 — The solution correctly applies Green's Theorem, computes the partial derivatives accurately, and sets up the polar integral with the correct Jacobian and bounds for the unit disk.
qwen3.6:27b-mlx: pass 2026-10-09 — The solution correctly applies Green's Theorem, computes the partial derivatives accurately, and evaluates the resulting double integral over the unit disk using polar coordinates.
gpt-oss:20b: pass 2026-10-09

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/greens_area, checked 2026-10-09 with SymPy 1.14.0.