∫Calc Practice

The divergence theorem

Problem 12.202 · easy

Use the divergence theorem to find the outward flux of \( \displaystyle \mathbf F = \left(x^{2}\right)\mathbf i + \left(y\right)\mathbf j + \left(z\right)\mathbf k \) across the sphere \( \displaystyle x^2 + y^2 + z^2 = 1 \).
  1. \[ \frac{d}{d x} x^{2} + \frac{d}{d y} y + \frac{d}{d z} z = 2 x + 2 \]
    div F.✓ Proved
  2. Flux out of a closed surface = ∭ div F dV over the solid inside it (in spherical coordinates).
  3. \[ \int\limits_{0}^{2 \pi}\int\limits_{0}^{\pi}\int\limits_{0}^{1} \rho^{2} \left(2 \rho \sin{\left(\phi \right)} \cos{\left(\theta \right)} + 2\right) \sin{\left(\phi \right)}\, d\rho\, d\phi\, d\theta = \frac{8 \pi}{3} \]
    The triple integral.✓ Proved
Answer \( \frac{8 \pi}{3} \)

Lines: 2 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Not checked—a sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the surface integral F·n dS over the sphere, computed directly

Reviewers

  • gpt-oss:20b: fail (error) — The divergence is correct, but the volume integral was evaluated incorrectly. The correct outward flux is 2π²/3, not 8π/3. The solution misapplies the integration of the constant term over the sphere.
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • gpt-oss:20b: fail (error) 2026-10-06 — The divergence is correct, but the volume integral was evaluated incorrectly. The correct outward flux is 2π²/3, not 8π/3. The solution misapplies the integration of the constant term over the sphere.
  • qwen3.6:27b-mlx: pass 2026-10-06
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: pass 2026-10-06 — The solution correctly applies the Divergence Theorem, computes the divergence as 2x + 2, and sets up the triple integral in spherical coordinates with correct bounds and Jacobian. The final result is correct.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/divergence_theorem, checked 2026-10-06 with SymPy 1.14.0.