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Triple integrals

Problem 11.99 · easy

Evaluate \( \displaystyle \iiint_B 2 x z \, dV \) where \( \displaystyle B = [0, 1] \times [0, 2] \times [0, 1] \).
  1. \[ \int\limits_{0}^{1} 2 x z\, dz = x \]
    Integrate in z.✓ Proved
  2. \[ \int\limits_{0}^{2} x\, dy = 2 x \]
    Then y.✓ Proved
  3. \[ \int\limits_{0}^{1} 2 x\, dx = 1 \]
    Then x.✓ Proved
Answer \( 1 \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The explanation has not been reviewed yet.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0a 40×40×40 midpoint sum over the box agrees to 1%

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/triple_integral_box, checked 2026-09-26 with SymPy 1.14.0.