Riemann sums for double integrals
Problem 11.525 · medium
Estimate \( \displaystyle \iint_R x^{2} + y \, dA \) over \( \displaystyle R = [0, 1] \times [0, 2] \) with a Riemann sum, \( \displaystyle m = 4 \) subintervals in \( \displaystyle x \) and \( \displaystyle n = 2 \) in \( \displaystyle y \), sampling at the midpoint points.
- \[ 2 \cdot \frac{1}{2} \cdot 1 \cdot \frac{1}{4} = \frac{1}{4} \]ΔA = Δx Δy.✓ Proved
- The sample points: (1/8, 1/2), (1/8, 3/2), (3/8, 1/2), (3/8, 3/2), (5/8, 1/2), (5/8, 3/2), (7/8, 1/2), (7/8, 3/2).Reviewed
- \[ 1 \cdot 1 \cdot \frac{1}{4} \left(\frac{33}{64} + \frac{41}{64} + \frac{57}{64} + \frac{81}{64} + \frac{97}{64} + \frac{105}{64} + \frac{121}{64} + \frac{145}{64}\right) = \frac{85}{32} \]ΔA times the sum of f at the sample points.✓ Proved
- \[ \int\limits_{0}^{2}\int\limits_{0}^{1} \left(x^{2} + y\right)\, dx\, dy = \frac{8}{3} \]For comparison, the exact value is 8/3.✓ Proved
Answer \( \frac{85}{32} \)
✓ Nihil obstat Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the sum recomputed in exact fractions |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the grid dimensions, midpoints, and function evaluations. The arithmetic is correct, and the comparison with the exact integral is valid.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly identifies the grid dimensions, midpoints, and function evaluations. The arithmetic is correct, and the comparison with the exact integral is valid.gpt-oss:20b: pass 2026-10-19qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the subrectangle area, lists the correct midpoints for the given grid, and computes the Riemann sum accurately. The comparison with the exact integral is also correct.gpt-oss:20b: pass 2026-10-17qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the subrectangle area, the midpoint sample points, and the resulting Riemann sum. The comparison with the exact integral is also correct.gpt-oss:20b: pass 2026-10-17
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/double_riemann, checked 2026-10-19 with SymPy 1.14.0.