Riemann sums for double integrals
Problem 11.445 · medium
Estimate \( \displaystyle \iint_R x^{2} + y \, dA \) over \( \displaystyle R = [0, 2] \times [0, 2] \) with a Riemann sum, \( \displaystyle m = 2 \) subintervals in \( \displaystyle x \) and \( \displaystyle n = 2 \) in \( \displaystyle y \), sampling at the midpoint points.
- \[ 2 \cdot \frac{1}{2} \cdot 2 \cdot \frac{1}{2} = 1 \]ΔA = Δx Δy.✓ Proved
- The sample points: (1/2, 1/2), (1/2, 3/2), (3/2, 1/2), (3/2, 3/2).Reviewed
- \[ 1 \cdot 1 \left(\frac{3}{4} + \frac{7}{4} + \frac{11}{4} + \frac{15}{4}\right) = 9 \]ΔA times the sum of f at the sample points.✓ Proved
- \[ \int\limits_{0}^{2}\int\limits_{0}^{2} \left(x^{2} + y\right)\, dx\, dy = \frac{28}{3} \]For comparison, the exact value is 28/3.✓ Proved
Answer \( 9 \)
✓ Nihil obstat Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the sum recomputed in exact fractions |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the subrectangle area and the midpoint sample points for the given grid. The arithmetic for the Riemann sum is correct, and the comparison with the exact integral is accurate.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-18 — The solution correctly identifies the subrectangle area and the midpoint sample points for the given grid. The arithmetic for the Riemann sum is correct, and the comparison with the exact integral is accurate.gpt-oss:20b: pass 2026-10-18qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly identifies the subrectangle area, the midpoint sample points, and the resulting Riemann sum. The comparison with the exact integral is also correct.gpt-oss:20b: pass 2026-10-15qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly identifies the subrectangle area and midpoints, computes the Riemann sum accurately, and provides the correct exact integral for comparison.gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/double_riemann, checked 2026-10-18 with SymPy 1.14.0.