Home›Calculus 3›Riemann sums for double integrals›Problem 11.392

Riemann sums for double integrals

Problem 11.392 · medium

Estimate \( \displaystyle \iint_R x^{2} + y \, dA \) over \( \displaystyle R = [0, 1] \times [0, 1] \) with a Riemann sum, \( \displaystyle m = 2 \) subintervals in \( \displaystyle x \) and \( \displaystyle n = 2 \) in \( \displaystyle y \), sampling at the midpoint points.

\[ 1 \cdot \frac{1}{2} \cdot 1 \cdot \frac{1}{2} = \frac{1}{4} \]
ΔA = Δx Δy.✓ Proved
The sample points: (1/4, 1/4), (1/4, 3/4), (3/4, 1/4), (3/4, 3/4).
Reviewed
\[ 1 \cdot \frac{1}{2} \cdot 1 \cdot \frac{1}{2} \left(\frac{5}{16} + \frac{13}{16} + \frac{13}{16} + \frac{21}{16}\right) = \frac{13}{16} \]
ΔA times the sum of f at the sample points.✓ Proved
\[ \int\limits_{0}^{1}\int\limits_{0}^{1} \left(x^{2} + y\right)\, dx\, dy = \frac{5}{6} \]
For comparison, the exact value is 5/6.✓ Proved

Answer \( \frac{13}{16} \)

✓ Nihil obstat Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt

Line	Status	Checked by	Detail
1	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
2	Reviewed	reviewers: gpt-oss:20b, qwen3.6:27b-mlx	a sentence; read, not computed
3	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
4	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
answer, a second way	✓ Checked independently	sympy 1.14.0 + mpmath 1.3.0	the sum recomputed in exact fractions

Reviewers

gpt-oss:20b: pass
qwen3.6:27b-mlx: pass — The solution correctly identifies the subinterval widths, midpoints, and function evaluations. The final summation and comparison with the exact integral are accurate.

Every verdict on record (6)

qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the subinterval widths, midpoints, and function evaluations. The final summation and comparison with the exact integral are accurate.
gpt-oss:20b: pass 2026-10-17
qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly identifies the subrectangle area, the midpoint sample points, and the function evaluations. The final summation and comparison with the exact integral are accurate.
gpt-oss:20b: pass 2026-10-15
qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly identifies the subinterval widths, midpoints, and function evaluations. The final calculation is correct.
gpt-oss:20b: pass 2026-10-14

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/double_riemann, checked 2026-10-17 with SymPy 1.14.0.