∫Calc Practice

Riemann sums for double integrals

Problem 11.389 · medium

Estimate \( \displaystyle \iint_R 3 x - y^{2} + 5 \, dA \) over \( \displaystyle R = [0, 4] \times [0, 1] \) with a Riemann sum, \( \displaystyle m = 2 \) subintervals in \( \displaystyle x \) and \( \displaystyle n = 2 \) in \( \displaystyle y \), sampling at the lower left corners.
  1. \[ 1 \cdot \frac{1}{2} \cdot 4 \cdot \frac{1}{2} = 1 \]
    ΔA = Δx Δy.✓ Proved
  2. The sample points: (0, 0), (0, 1/2), (2, 0), (2, 1/2).
    Reviewed
  3. \[ 2 \cdot 1 \cdot \frac{1}{2} \left(\frac{19}{4} + 5 + \frac{43}{4} + 11\right) = \frac{63}{2} \]
    ΔA times the sum of f at the sample points.✓ Proved
  4. \[ \int\limits_{0}^{1}\int\limits_{0}^{4} \left(3 x - y^{2} + 5\right)\, dx\, dy = \frac{128}{3} \]
    For comparison, the exact value is 128/3.✓ Proved
Answer \( \frac{63}{2} \)

Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the sum recomputed in exact fractions

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the subrectangle area and the lower-left sample points for the given grid. The arithmetic in the Riemann sum calculation is correct, and the comparison with the exact integral is accurate.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the subrectangle area and the lower-left sample points for the given grid. The arithmetic in the Riemann sum calculation is correct, and the comparison with the exact integral is accurate.
  • gpt-oss:20b: pass 2026-10-17
  • qwen3.6:27b-mlx: fail (error) 2026-10-15 — The sample points listed in step 2 are incorrect for a 2x2 grid with lower-left sampling. The correct points should be (0,0), (2,0), (0,0.5), and (2,0.5). The solution lists (0, 1/2) and (2, 1/2) but omits the points with y=0, effectively sampling the top-left and top-right corners of the bottom sub-rectangles or mixing up the indices, leading to an incorrect sum despite the final arithmetic matching the wrong inputs.
  • gpt-oss:20b: pass 2026-10-15
  • qwen3.6:27b-mlx: inconclusive 2026-10-14 — reviewer returned a non-object
  • gpt-oss:20b: pass 2026-10-14

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/double_riemann, checked 2026-10-17 with SymPy 1.14.0.