Jacobians and change of variables
Problem 11.335 · easy
Find the Jacobian \( \displaystyle \dfrac{\partial(x, y)}{\partial(u, v)} \) of the transformation \( \displaystyle x = - u + v \), \( \displaystyle y = 3 u - v \).
- \[ \left[\begin{matrix}\frac{\partial}{\partial u} \left(- u + v\right) & \frac{\partial}{\partial v} \left(- u + v\right)\\\frac{\partial}{\partial u} \left(3 u - v\right) & \frac{\partial}{\partial v} \left(3 u - v\right)\end{matrix}\right] = \left[\begin{matrix}-1 & 1\\3 & -1\end{matrix}\right] \]The matrix of partial derivatives.✓ Proved
- \[ -2 \]Its determinant: x_u·y_v − x_v·y_u.✓ Proved
- |J| is the factor by which the transformation stretches small areas: dA = |J| du dv.Reviewed
Answer \( -2 \)
Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the image of a tiny square measured by the shoelace formula |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly computes the Jacobian determinant as -2. The final sentence correctly distinguishes the Jacobian determinant (J) from the area scaling factor (|J|), which is a helpful clarification for students.
Every verdict on record (4)
gpt-oss:20b: pass 2026-10-10qwen3.6:27b-mlx: pass 2026-10-10 — The solution correctly computes the Jacobian determinant as -2. The final sentence correctly distinguishes the Jacobian determinant (J) from the area scaling factor (|J|), which is a helpful clarification for students.qwen3.6:27b-mlx: fail (misleading) 2026-10-10 — The problem asks for the Jacobian determinant, which is -2. Line 3 introduces the absolute value |J| for area scaling, which is irrelevant to finding the signed Jacobian and could confuse a student into thinking the answer should be positive.gpt-oss:20b: pass 2026-10-10
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/jacobian, checked 2026-10-10 with SymPy 1.14.0.