∫Calc Practice

Triple integrals in cylindrical coordinates

Problem 11.297 · easy

Use cylindrical coordinates to find the volume of the solid inside \( \displaystyle x^2 + y^2 = 1 \), above \( \displaystyle z = 0 \) and below \( \displaystyle z = 2 - x^2 - y^2 \).
  1. In cylindrical coordinates x² + y² = r² and dV = r dz dr dθ; the region is 0 ≤ θ ≤ 2π, 0 ≤ r ≤ R and z between the surfaces.
  2. \[ \int\limits_{0}^{2 \pi}\int\limits_{0}^{1}\int\limits_{0}^{2 - r^{2}} r\, dz\, dr\, d\theta = \frac{3 \pi}{2} \]
    The iterated integral.✓ Proved
Answer \( \frac{3 \pi}{2} \approx 4.71239 \)

Lines: 1 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0nested quadrature in rectangular coordinates

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (style) — [domain objection, downgraded to style] The setup in line 1 is incomplete because it leaves the radial bound 'R' undefined, failing to specify that R=1 based on the cylinder x^2+y^2=1. This omission makes the logical connection between the problem statement and the integral in line 2 unclear.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: fail (style) 2026-10-07 — [domain objection, downgraded to style] The setup in line 1 is incomplete because it leaves the radial bound 'R' undefined, failing to specify that R=1 based on the cylinder x^2+y^2=1. This omission makes the logical connection between the problem statement and the integral in line 2 unclear.
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: fail (style) 2026-10-07 — [domain objection, downgraded to style] The solution fails to explicitly define the upper bound for r (R=1) derived from the intersection of the cylinder x^2+y^2=1 and the paraboloid, leaving the variable R undefined in the setup sentence. Additionally, the integral line is marked 'unchecked' despite the instructions stating equations are checked by a CAS, creating a contradiction in the review protocol.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/cylindrical_integral, checked 2026-10-07 with SymPy 1.14.0.