∫Calc Practice

Jacobians and change of variables

Problem 11.258 · easy

Find the Jacobian \( \displaystyle \dfrac{\partial(x, y)}{\partial(u, v)} \) of the transformation \( \displaystyle x = 3 u - 2 v \), \( \displaystyle y = - u - v \).
  1. \[ \left[\begin{matrix}\frac{\partial}{\partial u} \left(3 u - 2 v\right) & \frac{\partial}{\partial v} \left(3 u - 2 v\right)\\\frac{\partial}{\partial u} \left(- u - v\right) & \frac{\partial}{\partial v} \left(- u - v\right)\end{matrix}\right] = \left[\begin{matrix}3 & -2\\-1 & -1\end{matrix}\right] \]
    The matrix of partial derivatives.✓ Proved
  2. \[ -5 \]
    Its determinant: x_u·y_v − x_v·y_u.✓ Proved
  3. |J| is the factor by which the transformation stretches small areas: dA = |J| du dv.
    Reviewed
Answer \( -5 \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the image of a tiny square measured by the shoelace formula

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly calculates the Jacobian determinant as -5. The final sentence correctly distinguishes the Jacobian determinant from the area scaling factor (absolute value), which is standard and helpful context.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: pass 2026-10-06 — The solution correctly calculates the Jacobian determinant as -5. The final sentence correctly distinguishes the Jacobian determinant from the area scaling factor (absolute value), which is standard and helpful context.
  • qwen3.6:27b-mlx: pass 2026-10-06
  • gpt-oss:20b: pass 2026-10-06

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/jacobian, checked 2026-10-06 with SymPy 1.14.0.