∫Calc Practice

Level curves and domains

Problem 10.573 · easy Video

Find the equation of the level curve of \( \displaystyle f(x, y) = 2 x + 2 y \) that passes through \( \displaystyle (1, 1) \), and describe it.
  1. A level curve is f(x, y) = c; the point fixes c.
    Reviewed
  2. \[ \left. 2 x + 2 y \right|_{\substack{ x=1\\ y=1 }} = 4 \]
    c = f(1, 1).✓ Proved
  3. So the level curve is Eq(2*x + 2*y, 4), a line.
    Reviewed
Answer \( 2 x + 2 y = 4\ (\text{a line}) \)
A contour map of f(x, y) = 2x + 2y: each curve joins points where f has the same value. The level curve through (1, 1) is highlighted.

✓ Nihil obstat Lines: 1 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0points found numerically on the claimed curve near P give f the same value

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-17
  • gpt-oss:20b: pass 2026-10-17
  • qwen3.6:27b-mlx: pass 2026-10-15
  • gpt-oss:20b: pass 2026-10-15
  • qwen3.6:27b-mlx: pass 2026-10-14
  • gpt-oss:20b: pass 2026-10-14

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/level_curves, checked 2026-10-17 with SymPy 1.14.0.