∫Calc Practice

Absolute extrema on a closed region

Problem 10.453 · medium

Find the absolute maximum and minimum values of \( \displaystyle f(x, y) = - 2 x^{2} + x y - 2 x + 2 y^{2} + 3 y \) on the rectangle \( \displaystyle -2 \le x \le 3 \), \( \displaystyle 0 \le y \le 3 \).
  1. \[ \left[\begin{matrix}\frac{\partial}{\partial x} \left(- 2 x^{2} + x y - 2 x + 2 y^{2} + 3 y\right)\\\frac{\partial}{\partial y} \left(- 2 x^{2} + x y - 2 x + 2 y^{2} + 3 y\right)\end{matrix}\right] = \left[\begin{matrix}- 4 x + y - 2\\x + 4 y + 3\end{matrix}\right] \]
    Interior critical points solve ∇f = 0.✓ Proved
  2. On each edge f is a function of one variable: find its critical points there too, and include the four corners.
  3. \[ \left[\begin{matrix}-4\\17\\1 \cdot \frac{1}{2}\\\frac{217}{8}\\-24\\12\end{matrix}\right] = \left[\begin{matrix}-4\\17\\\frac{1}{2}\\\frac{217}{8}\\-24\\12\end{matrix}\right] \]
    f at every candidate: (-2, 0), (-2, 3), (-1/2, 0), (1/4, 3), (3, 0), (3, 3).✓ Proved
  4. The largest value is 217/8, the smallest -24.
Answer \( \max = \frac{217}{8}\ \text{at}\ (\frac{1}{4}, 3);\ \min = -24\ \text{at}\ (3, 0) \)

Lines: 2 proved, 2 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Not checked—a sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Not checked—a sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0f sampled on a 241 × 241 grid never beats the claimed max or min, and comes within 5% of both

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: inconclusive — reviewer returned a non-object
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-09
  • qwen3.6:27b-mlx: inconclusive 2026-10-09 — reviewer returned a non-object
  • gpt-oss:20b: fail (style) 2026-10-09 — [domain objection, downgraded to style] The minimum value is incorrectly reported. f(3,0) = -18, not -24, and no other point in the rectangle attains -24. The solution also lists an interior point (-1/2,0) that lies on the boundary, but the interior critical point actually lies outside the domain. Thus the conclusion about the absolute extrema is false.
  • qwen3.6:27b-mlx: fail (error) 2026-10-09 — The solution fails to identify the interior critical point (-1/2, 3/8) and incorrectly lists (-1/2, 0) as a candidate, which is not a critical point on the boundary y=0. Consequently, the global minimum is likely incorrect.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/absolute_extrema_2var, checked 2026-10-09 with SymPy 1.14.0.