∫Calc Practice

The multivariable chain rule

Problem 10.444 · medium

Let \( \displaystyle z = \sqrt{x^{2} + y^{2} + 4} \) with \( \displaystyle x = e^{t} \), \( \displaystyle y = 2 t \). Use the chain rule to find \( \displaystyle \frac{dz}{dt} \) at \( \displaystyle t = 0 \).
  1. \[ \left[\begin{matrix}\frac{\partial}{\partial x} \sqrt{x^{2} + y^{2} + 4}\\\frac{\partial}{\partial y} \sqrt{x^{2} + y^{2} + 4}\end{matrix}\right] = \left[\begin{matrix}\frac{x}{\sqrt{x^{2} + y^{2} + 4}}\\\frac{y}{\sqrt{x^{2} + y^{2} + 4}}\end{matrix}\right] \]
    ∂z/∂x and ∂z/∂y.✓ Proved
  2. dz/dt = (∂z/∂x)(dx/dt) + (∂z/∂y)(dy/dt).
  3. \[ \frac{\sqrt{5}}{5} \]
    At t = 0, where (x, y) = (1, 0).✓ Proved
Answer \( \frac{\sqrt{5}}{5} \)

Lines: 2 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Not checked—a sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0substituted first, then differenced numerically

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (error) — The solution fails to explicitly calculate or state the values of dx/dt and dy/dt at t=0, which are necessary components of the chain rule formula stated in step 2. Without showing these derivatives, the jump to the final numerical answer in step 3 is unjustified and skips the core calculation required by the problem.
Every verdict on record (4)
  • qwen3.6:27b-mlx: fail (error) 2026-10-08 — The solution fails to explicitly calculate or state the values of dx/dt and dy/dt at t=0, which are necessary components of the chain rule formula stated in step 2. Without showing these derivatives, the jump to the final numerical answer in step 3 is unjustified and skips the core calculation required by the problem.
  • gpt-oss:20b: pass 2026-10-08
  • gpt-oss:20b: pass 2026-10-08
  • qwen3.6:27b-mlx: fail (error) 2026-10-08 — The solution fails to explicitly calculate or state the values of dx/dt and dy/dt at t=0, which are necessary components of the chain rule formula stated in step 2. Without showing these derivatives, the jump to the final numerical answer is unjustified and hides the actual computation.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/multivariable_chain_rule, checked 2026-10-08 with SymPy 1.14.0.