∫Calc Practice

The multivariable chain rule

Problem 10.394 · easy

Let \( \displaystyle z = x^{2} - x y + 3 y^{2} \) with \( \displaystyle x = s + 2 t \), \( \displaystyle y = s - t \). Find \( \displaystyle \frac{\partial z}{\partial s} \) at \( \displaystyle s = 1 \), \( \displaystyle t = 0 \).
  1. \[ \left[\begin{matrix}\frac{\partial}{\partial x} \left(x^{2} - x y + 3 y^{2}\right)\\\frac{\partial}{\partial y} \left(x^{2} - x y + 3 y^{2}\right)\end{matrix}\right] = \left[\begin{matrix}2 x - y\\- x + 6 y\end{matrix}\right] \]
    ∂z/∂x and ∂z/∂y.✓ Proved
  2. ∂z/∂s = (∂z/∂x)(∂x/∂s) + (∂z/∂y)(∂y/∂s).
    Reviewed
  3. \[ 6 \]
    Substitute.✓ Proved
Answer \( 6 \)

Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0substituted first, then differenced numerically

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the multivariable chain rule and the final substitution yields the correct result.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: pass 2026-10-06 — The solution correctly applies the multivariable chain rule and the final substitution yields the correct result.
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: fail (error) 2026-10-06 — The solution fails to explicitly calculate or state the partial derivatives of x and y with respect to s (∂x/∂s = 1, ∂y/∂s = 1) and the values of x and y at the given point (x=1, y=1). It jumps directly to the final numerical result without showing the necessary intermediate steps, making the derivation incomplete and opaque.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/multivariable_chain_rule, checked 2026-10-06 with SymPy 1.14.0.