Home›Calculus 3›Implicit differentiation with partial derivatives›Problem 10.363

Implicit differentiation with partial derivatives

Problem 10.363 · easy

Use partial derivatives to find \( \displaystyle \frac{dy}{dx} \) at \( \displaystyle (-1, -1) \) for the curve \( \displaystyle x^{3} - 3 x y + y^{3} = -5 \).

\[ \left[\begin{matrix}\frac{\partial}{\partial x} \left(x^{3} - 3 x y + y^{3}\right)\\\frac{\partial}{\partial y} \left(x^{3} - 3 x y + y^{3}\right)\end{matrix}\right] = \left[\begin{matrix}3 x^{2} - 3 y\\- 3 x + 3 y^{2}\end{matrix}\right] \]
F_x and F_y.✓ Proved
\[ -1 \]
dy/dx = −F_x/F_y at the point.✓ Proved

Answer \( -1 \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt

Line	Status	Checked by	Detail
1	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
2	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
answer, a second way	✓ Checked independently	sympy 1.14.0 + mpmath 1.3.0	solved the equation numerically near the point and differenced

Reviewers

gpt-oss:20b: pass
qwen3.6:27b-mlx: fail (error) — The solution fails to evaluate the partial derivatives at the point (-1, -1) before computing the ratio. It states the final answer is -1, but does not show the substitution of x=-1 and y=-1 into the expressions for F_x and F_y derived in step 1.

Every verdict on record (4)

gpt-oss:20b: pass 2026-10-06
qwen3.6:27b-mlx: fail (error) 2026-10-06 — The solution fails to evaluate the partial derivatives at the point (-1, -1) before computing the ratio. It states the final answer is -1, but does not show the substitution of x=-1 and y=-1 into the expressions for F_x and F_y derived in step 1.
gpt-oss:20b: pass 2026-10-06
qwen3.6:27b-mlx: fail (error) 2026-10-06 — The solution fails to evaluate the partial derivatives at the specific point (-1, -1) before computing the ratio. It presents the symbolic expressions for F_x and F_y but jumps directly to the final numerical answer without showing the substitution step, making the logic opaque and incomplete.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/implicit_partials, checked 2026-10-06 with SymPy 1.14.0.