∫Calc Practice

Linear approximation in two variables

Problem 10.325 · hard

Find the linear approximation of \( \displaystyle f(x, y) = x \sqrt{y} \) at \( \displaystyle (1, 4) \), and use it to estimate \( \displaystyle f\left(\frac{11}{10}, \frac{39}{10}\right) \).
  1. \[ \left[\begin{matrix}\frac{\partial}{\partial x} x \sqrt{y}\\\frac{\partial}{\partial y} x \sqrt{y}\end{matrix}\right] = \left[\begin{matrix}\sqrt{y}\\\frac{x}{2 \sqrt{y}}\end{matrix}\right] \]
    f_x and f_y.✓ Proved
  2. \[ \left[\begin{matrix}2\\2\\1 \cdot \frac{1}{4}\end{matrix}\right] = \left[\begin{matrix}2\\2\\\frac{1}{4}\end{matrix}\right] \]
    f, f_x and f_y at the point.✓ Proved
  3. \[ 2 x + \frac{y}{4} - 1 \]
    The linearization.✓ Proved
  4. \[ \frac{87}{40} \]
    The estimate; the true value is about 2.17233.✓ Proved
Answer \( L(x, y) = 2 x + \frac{y}{4} - 1,\ f \approx \frac{87}{40} = 2.17500 \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0L agrees with f to within O(h²) in four directions at h = 1e−5

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly computes the partial derivatives, evaluates them at the given point, constructs the linearization formula, and uses it to estimate the function value. All steps are logically sound and algebraically correct.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly computes the partial derivatives, evaluates them at the given point, constructs the linearization formula, and uses it to estimate the function value. All steps are logically sound and algebraically correct.
  • gpt-oss:20b: pass 2026-10-04
  • qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly computes the partial derivatives, evaluates them at the given point, constructs the linear approximation formula, and uses it to estimate the function value. The algebraic steps are verified and the logic is sound.
  • gpt-oss:20b: pass 2026-10-04

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/linear_approx_2var, checked 2026-10-04 with SymPy 1.14.0.