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Lagrange multipliers

Problem 10.200 · medium Video

Use Lagrange multipliers to find the maximum and minimum of \( \displaystyle f(x, y) = 2 x + y \) on the circle \( \displaystyle x^2 + y^2 = 9 \).
  1. Solve ∇f = λ∇g with g(x, y) = x² + y² − r² = 0.
  2. \[ \left[\begin{matrix}\frac{\partial}{\partial x} \left(2 x + y\right)\\\frac{\partial}{\partial y} \left(2 x + y\right)\end{matrix}\right] = \left[\begin{matrix}2\\1\end{matrix}\right] \]
    ∇f.✓ Proved
  3. \[ \left[\begin{matrix}\frac{\partial}{\partial x} \left(x^{2} + y^{2} - 9\right)\\\frac{\partial}{\partial y} \left(x^{2} + y^{2} - 9\right)\end{matrix}\right] = \left[\begin{matrix}2 x\\2 y\end{matrix}\right] \]
    ∇g.✓ Proved
  4. So x = 2/(2λ), y = 1/(2λ); substituting into the constraint gives λ = ±√(5)/(2√9).
  5. \[ 3 \sqrt{5} \]
    The maximum; the minimum is its negative.
Answer \( \max = 3 \sqrt{5},\ \min = - 3 \sqrt{5} \)
A contour map of f(x, y) = 2x + y: each curve joins points where f has the same value. The constraint circle of radius 3 is drawn over it; the largest and smallest values on the circle are where a level line just touches it.

Lines: 2 proved, 3 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Not checked—a sentence; read, not computed
5Not checked—both sides are the same expression: the line states a value, and the working that produced it is not on the line
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0f around 100,000 points of the circle tops out at the same value

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (error) — The solution fails to explicitly solve for the coordinates (x, y) or substitute them back into f(x, y) to derive the final value. It jumps from the value of lambda to the final answer without showing the critical step of evaluating f at the critical points.
Every verdict on record (6)
  • qwen3.6:27b-mlx: fail (error) 2026-09-28 — The solution fails to explicitly solve for the coordinates (x, y) or substitute them back into f(x, y) to derive the final value. It jumps from the value of lambda to the final answer without showing the critical step of evaluating f at the critical points.
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly sets up the Lagrange multiplier equations, solves for x and y in terms of lambda, substitutes into the constraint to find lambda, and correctly identifies the maximum and minimum values.
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly sets up the Lagrange multiplier equations, solves for x and y in terms of lambda, substitutes into the constraint to find lambda, and correctly identifies the maximum and minimum values.
  • gpt-oss:20b: pass 2026-09-27

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/lagrange_multipliers, checked 2026-10-13 with SymPy 1.14.0.