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Partial derivatives

Problem 10.143 · hard

For \( \displaystyle f(x, y) = 3 x^{2} y - 2 x y^{3} \), find \( \displaystyle f_x \), \( \displaystyle f_y \) and \( \displaystyle f_{xy} \).
  1. For f_x hold y constant; for f_y hold x constant.
    Reviewed
  2. \[ \frac{\partial}{\partial x} \left(3 x^{2} y - 2 x y^{3}\right) = 2 y \left(3 x - y^{2}\right) \]
    f_x.✓ Proved
  3. \[ \frac{\partial}{\partial y} \left(3 x^{2} y - 2 x y^{3}\right) = 3 x \left(x - 2 y^{2}\right) \]
    f_y.✓ Proved
  4. \[ \frac{\partial}{\partial y} 2 y \left(3 x - y^{2}\right) = 6 x - 6 y^{2} \]
    f_xy: differentiate f_x with respect to y.✓ Proved
  5. \[ \frac{\partial}{\partial x} 3 x \left(x - 2 y^{2}\right) = 6 x - 6 y^{2} \]
    Clairaut: f_yx is the same.✓ Proved
Answer \( f_x = 2 y \left(3 x - y^{2}\right),\quad f_y = 3 x \left(x - 2 y^{2}\right),\quad f_{xy} = 6 x - 6 y^{2} \)

✓ Nihil obstat Lines: 4 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0difference quotients of f at (0.6, 0.4) agree with f_x and f_y

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly computes the partial derivatives and verifies Clairaut's theorem. The setup and steps are logically sound and algebraically correct.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly computes the partial derivatives and verifies Clairaut's theorem. The setup and steps are logically sound and algebraically correct.
  • gpt-oss:20b: pass 2026-09-26
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly computes the partial derivatives and verifies Clairaut's theorem. The setup and calculations are accurate.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/partial_derivatives, checked 2026-09-26 with SymPy 1.14.0.