∫Calc Practice

Gradient and directional derivatives

Problem 10.11 · medium Video

Find the directional derivative of \( \displaystyle f(x, y) = \sqrt{x^{2} + y^{2}} \) at \( \displaystyle (1, 0) \) in the direction of \( \displaystyle \langle 1, 0 \rangle \).
  1. \[ \left[\begin{matrix}\frac{\partial}{\partial x} \sqrt{x^{2} + y^{2}}\\\frac{\partial}{\partial y} \sqrt{x^{2} + y^{2}}\end{matrix}\right] = \left[\begin{matrix}\frac{x}{\sqrt{x^{2} + y^{2}}}\\\frac{y}{\sqrt{x^{2} + y^{2}}}\end{matrix}\right] \]
    ∇f.✓ Proved
  2. \[ \left[\begin{matrix}1\\0\end{matrix}\right] \]
    ∇f at the point.Reviewed
  3. \[ \left[\begin{matrix}1\\0\end{matrix}\right] \]
    The unit direction u.Reviewed
  4. \[ 1 \]
    D_u f = ∇f · u.Reviewed
Answer \( 1 \)
A contour map of f(x, y) = sqrt(x² + y²): each curve joins points where f has the same value. At (1, 0) the gradient arrow points straight uphill, across the contours, and the direction of travel is drawn beside it.

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxboth sides are the same expression: the line states a value, and the working that produced it is not on the line
3Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxboth sides are the same expression: the line states a value, and the working that produced it is not on the line
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxboth sides are the same expression: the line states a value, and the working that produced it is not on the line
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0f differenced along the unit direction agrees

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly computes the gradient, evaluates it at the point, identifies the unit direction vector, and calculates the dot product. The logic is sound and the result is correct.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-09-28 — The solution correctly computes the gradient, evaluates it at the point, identifies the unit direction vector, and calculates the dot product. The logic is sound and the result is correct.
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly computes the gradient, evaluates it at the given point, identifies the unit direction vector, and calculates the dot product to find the directional derivative.
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly computes the gradient, evaluates it at the given point, identifies the unit direction vector, and calculates the dot product to find the directional derivative.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/gradient_directional, checked 2026-10-13 with SymPy 1.14.0.