∫Calc Practice

Intermediate Value Theorem: locating a root

Problem 1.826 · medium

Show that \( \displaystyle x^{3} - 3 x + 6 = 0 \) has a solution in \( \displaystyle [-3, -2] \), then use two steps of bisection to find an interval of length \( \displaystyle \tfrac14 \) containing it.
  1. f is continuous on [-3, -2] (it is built from continuous functions), so the IVT applies.
    Reviewed
  2. \[ \left. x^{3} - 3 x + 6 \right|_{\substack{ x=-3 }} = -12 \]
    f(-3).✓ Proved
  3. \[ \left. x^{3} - 3 x + 6 \right|_{\substack{ x=-2 }} = 4 \]
    f(-2): the opposite sign, so a root lies between.✓ Proved
  4. \[ \left. x^{3} - 3 x + 6 \right|_{\substack{ x=- \frac{5}{2} }} = - \frac{17}{8} \]
    f(-5/2) ≈ -2.1250.✓ Proved
  5. \[ \left. x^{3} - 3 x + 6 \right|_{\substack{ x=- \frac{9}{4} }} = \frac{87}{64} \]
    f(-9/4) ≈ 1.3594.✓ Proved
  6. The sign changes on [-5/2, -9/4], so a root lies there.
    Reviewed
Answer \( \left[- \frac{5}{2}, - \frac{9}{4}\right] \)

Lines: 4 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0mpmath's bisection finds the root inside the claimed interval

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the Intermediate Value Theorem and performs two steps of bisection, arriving at the correct interval of length 1/4.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-11-12 — The solution correctly applies the Intermediate Value Theorem and performs two steps of bisection, arriving at the correct interval of length 1/4.
  • gpt-oss:20b: pass 2026-11-12
  • qwen3.6:27b-mlx: pass 2026-11-11
  • gpt-oss:20b: pass 2026-11-11
  • qwen3.6:27b-mlx: fail (error) 2026-11-11 — The interval notation in the final answer and step 6 is incorrect because the lower bound (-5/2) is greater than the upper bound (-9/4). The correct interval is [-9/4, -5/2].
  • gpt-oss:20b: pass 2026-11-11

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/ivt_root, checked 2026-11-12 with SymPy 1.14.0.