The squeeze theorem
Problem 1.710 · medium
Use the squeeze theorem to find \( \displaystyle \lim_{x \to \infty} \frac{\cos{\left(2 x \right)}}{x} \).
- Since −1 ≤ cos(·) ≤ 1, the expression lies between -1/x and 1/x.Reviewed
- \[ \lim_{x \to \infty}\left(- \frac{1}{x}\right) = 0 \]The lower bound's limit.✓ Proved
- \[ \lim_{x \to \infty} \frac{1}{x} = 0 \]The upper bound's limit, the same.✓ Proved
- Both bounds tend to the same value, so the expression trapped between them does too.Reviewed
Answer \( 0 \)
✓ Nihil obstat Lines: 2 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the expression evaluated ever closer to the limit point |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies the Squeeze Theorem. The bounds are valid for x > 0, and the limits of the bounding functions are correctly identified as 0.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly applies the Squeeze Theorem. The bounds are valid for x > 0, and the limits of the bounding functions are correctly identified as 0.gpt-oss:20b: pass 2026-10-19qwen3.6:27b-mlx: pass 2026-10-16 — The solution correctly applies the Squeeze Theorem by establishing valid bounds for the cosine term and showing that both bounds converge to 0 as x approaches infinity.gpt-oss:20b: pass 2026-10-16qwen3.6:27b-mlx: fail (style) 2026-10-15 — [domain objection, downgraded to style] The squeeze theorem requires the inequality to hold for all x in a neighborhood of the limit point. For x approaching infinity from the left (negative x), dividing by x reverses the inequalities, so -1/x is not a lower bound. The solution fails to restrict x to positive values or use absolute values.gpt-oss:20b: pass 2026-10-15
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/squeeze_theorem, checked 2026-10-19 with SymPy 1.14.0.