The squeeze theorem
Problem 1.690 · medium
Use the squeeze theorem to find \( \displaystyle \lim_{x \to 0} x^{3} \sin{\left(\frac{2}{x} \right)} \).
- Since −1 ≤ sin(·) ≤ 1, the expression lies between -x**2*Abs(x) and x**2*Abs(x).Reviewed
- \[ \lim_{x \to 0}\left(- x^{2} \left|{x}\right|\right) = 0 \]The lower bound's limit.✓ Proved
- \[ \lim_{x \to 0}\left(x^{2} \left|{x}\right|\right) = 0 \]The upper bound's limit, the same.✓ Proved
- Both bounds tend to the same value, so the expression trapped between them does too.Reviewed
Answer \( 0 \)
Lines: 2 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the expression evaluated ever closer to the limit point |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies the squeeze theorem by bounding the sine term and showing the resulting bounds converge to 0.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-18 — The solution correctly applies the squeeze theorem by bounding the sine term and showing the resulting bounds converge to 0.gpt-oss:20b: pass 2026-10-18qwen3.6:27b-mlx: fail (error) 2026-10-16 — The bounds in step 1 are incorrect; multiplying -1 <= sin(2/x) <= 1 by x^3 yields -|x|^3 <= x^3 sin(2/x) <= |x|^3, not -x^2|x|. The exponents do not match the problem statement.gpt-oss:20b: pass 2026-10-16qwen3.6:27b-mlx: fail (error) 2026-10-15 — The bounds derived in step 1 are incorrect. Since |sin(2/x)| <= 1, the expression x^3 sin(2/x) is bounded by -|x^3| and |x^3|, not -x^2|x| and x^2|x|. While the final limit is correct, the squeeze theorem is applied to the wrong functions, which is a mathematical error in the proof structure.gpt-oss:20b: pass 2026-10-15
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/squeeze_theorem, checked 2026-10-18 with SymPy 1.14.0.