The squeeze theorem
Problem 1.622 · medium
Use the squeeze theorem to find \( \displaystyle \lim_{x \to \infty} 2 + \frac{\cos{\left(2 x \right)}}{x} \).
- Since −1 ≤ cos(·) ≤ 1, the expression lies between 2 - 1/x and 2 + 1/x.
- \[ \lim_{x \to \infty}\left(2 - \frac{1}{x}\right) = 2 \]The lower bound's limit.✓ Proved
- \[ \lim_{x \to \infty}\left(2 + \frac{1}{x}\right) = 2 \]The upper bound's limit, the same.✓ Proved
- Both bounds tend to the same value, so the expression trapped between them does too.
Answer \( 2 \)
Lines: 2 proved, 2 not checked. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | Not checked | — | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the expression evaluated ever closer to the limit point |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (style) — [domain objection, downgraded to style] The squeeze theorem requires the inequalities to hold in a neighborhood of the limit point. For x < 0, dividing by x reverses the inequalities, so the bounds are swapped and the squeeze argument fails for x -> -infinity. The solution implicitly assumes x > 0 without stating it.
Every verdict on record (6)
qwen3.6:27b-mlx: fail (style) 2026-10-17 — [domain objection, downgraded to style] The squeeze theorem requires the inequalities to hold in a neighborhood of the limit point. For x < 0, dividing by x reverses the inequalities, so the bounds are swapped and the squeeze argument fails for x -> -infinity. The solution implicitly assumes x > 0 without stating it.gpt-oss:20b: pass 2026-10-17qwen3.6:27b-mlx: fail (style) 2026-10-14 — [domain objection, downgraded to style] The squeeze theorem requires the inequality to hold in a neighborhood of the limit point. For x < 0, dividing by x reverses the inequality, so the bounds are swapped and the squeeze does not apply as stated. The solution fails to restrict x to positive values.gpt-oss:20b: pass 2026-10-14qwen3.6:27b-mlx: fail (style) 2026-10-14 — [domain objection, downgraded to style] The squeeze theorem requires the inequalities to hold in a neighborhood of the limit point. The solution fails to restrict x to positive values (x > 0), where 1/x is positive, making the bounds 2 - 1/x and 2 + 1/x valid. For x < 0, the inequalities are reversed, so the stated bounds do not trap the function.gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/squeeze_theorem, checked 2026-10-17 with SymPy 1.14.0.