∫Calc Practice

One-sided limits of piecewise functions

Problem 1.261 · easy

Let \( \displaystyle f(x) = \begin{cases} 3 - x & x < 0 \\ -2 & x = 0 \\ 2 x^{2} + 2 x & x > 0 \end{cases} \). Find \( \displaystyle \lim_{x\to 0^-} f(x) \), \( \displaystyle \lim_{x\to 0^+} f(x) \), \( \displaystyle \lim_{x\to 0} f(x) \) and \( \displaystyle f(0) \).
  1. For x < 0 only the first piece matters, so the left-hand limit is the limit of that polynomial.
    Reviewed
  2. \[ \lim_{x \to 0^-}\left(3 - x\right) = 3 \]
    Left-hand limit.✓ Proved
  3. \[ \lim_{x \to 0^+}\left(2 x^{2} + 2 x\right) = 0 \]
    Right-hand limit.✓ Proved
  4. The one-sided limits are different, so the two-sided limit does not exist.
    Reviewed
  5. The value f(0) = -2 is read straight from the middle line; it does not affect any of the limits.
    Reviewed
Answer \( \lim_{x\to 0^-} f(x) = 3,\ \lim_{x\to 0^+} f(x) = 0,\ \lim_{x\to a} f(x) \text{ does not exist},\ f(0) = -2 \)

✓ Nihil obstat Lines: 2 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
5Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the pieces evaluated at a ± 1e-12

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the relevant pieces for the one-sided limits, verifies their values, and correctly concludes that the two-sided limit does not exist because the one-sided limits differ. The value of f(0) is correctly identified and its independence from the limits is correctly stated.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-05 — The solution correctly identifies the relevant pieces for the one-sided limits, verifies their values, and correctly concludes that the two-sided limit does not exist because the one-sided limits differ. The value of f(0) is correctly identified and its independence from the limits is correctly stated.
  • gpt-oss:20b: pass 2026-10-05
  • qwen3.6:27b-mlx: pass 2026-10-05 — The solution correctly identifies the relevant pieces for the one-sided limits, computes them accurately, and correctly concludes that the two-sided limit does not exist due to the mismatch. The value of f(0) is also correctly identified.
  • gpt-oss:20b: pass 2026-10-05

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/one_sided_limits, checked 2026-10-05 with SymPy 1.14.0.