∫Calc Practice

Continuity and types of discontinuity

Problem 1.195 · hard

Find every point where \( \displaystyle f(x) = \frac{2 x^{2} - 2}{x^{2} - x - 2} \) is discontinuous, and classify each discontinuity as removable, a jump, or infinite.
  1. A rational function is continuous wherever its denominator is not zero, so only the zeros of the denominator can be discontinuities.
  2. \[ x^{2} - x - 2 = \left(x - 2\right) \left(x + 1\right) \]
    Factor the denominator.✓ Proved
  3. \[ \frac{2 x^{2} - 2}{x^{2} - x - 2} = \frac{2 x - 2}{x - 2} \]
    The factor (x + 1) cancels.✓ Proved
  4. \[ \lim_{x \to -1^+}\left(\frac{2 x^{2} - 2}{x^{2} - x - 2}\right) = \frac{4}{3} \]
    At x = -1 the limit exists, but f(-1) is undefined: a removable discontinuity.✓ Proved
  5. \[ \left. 2 x - 2 \right|_{\substack{ x=2 }} = 2 \]
    At x = 2 the numerator is not 0 while the denominator is, so |f(x)| grows without bound: an infinite discontinuity.✓ Proved
Answer \( \text{removable at } x = -1;\ \text{infinite at } x = 2 \)

Lines: 4 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0zeros of the denominator found by solve, each probed at ±1e-9: {-1: 'removable', 2: 'infinite'}

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: inconclusive — reviewer response could not be parsed: {"verdict": "fail", "severity": "error", "notes": "The solution incorrectly claims that the limit at x = -1 is 4/3; the correct limit is 4/3 only if the simplified function is (2x-2)/(x-2) evaluated a
Every verdict on record (4)
  • qwen3.6:27b-mlx: inconclusive 2026-10-04 — reviewer response could not be parsed: {"verdict": "fail", "severity": "error", "notes": "The solution incorrectly claims that the limit at x = -1 is 4/3; the correct limit is 4/3 only if the simplified function is (2x-2)/(x-2) evaluated a
  • gpt-oss:20b: pass 2026-10-04
  • qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly identifies the points of discontinuity, simplifies the function to classify them, and applies the correct definitions for removable and infinite discontinuities.
  • gpt-oss:20b: pass 2026-10-04

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/continuity_classify, checked 2026-10-04 with SymPy 1.14.0.