Vertical and horizontal asymptotes
Problem 1.180 · medium
Find all vertical and horizontal asymptotes of \( \displaystyle f(x) = \frac{- 3 x^{2} - 12 x - 12}{x^{2} - 16} \).
- \[ x^{2} - 16 = \left(x - 4\right) \left(x + 4\right) \]Factor the denominator.✓ Proved
- The numerator is not zero at x = -4 or x = 4, so both are vertical asymptotes.Reviewed
- \[ \lim_{x \to \infty}\left(\frac{- 3 x^{2} - 12 x - 12}{x^{2} - 16}\right) = -3 \]Divide through by the highest power of x in the denominator.✓ Proved
- \[ \lim_{x \to -\infty}\left(\frac{- 3 x^{2} - 12 x - 12}{x^{2} - 16}\right) = -3 \]The same as x → −∞.✓ Proved
Answer \( x = -4,\ x = 4;\ y = -3 \)
✓ Nihil obstat Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | f probed just beside each vertical asymptote and at x = ±1e9 |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the vertical asymptotes by verifying the denominator is zero and the numerator is non-zero at those points. It also correctly computes the horizontal asymptote using limits at infinity.
Every verdict on record (4)
qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly identifies the vertical asymptotes by verifying the denominator is zero and the numerator is non-zero at those points. It also correctly computes the horizontal asymptote using limits at infinity.gpt-oss:20b: pass 2026-10-04qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly identifies the vertical asymptotes by checking that the denominator is zero while the numerator is non-zero. It also correctly determines the horizontal asymptote by evaluating the limits at infinity.gpt-oss:20b: pass 2026-10-04
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/asymptotes, checked 2026-10-04 with SymPy 1.14.0.